I am making a Tic Tac Toe game and i created a function that inserts X or O into my array. I have run into one problem with my design. I call the function to make a move for X, but when it is the next players turn how do i make it call for O?
Is there a way after i put makeMove() i can just call somehow it to take in O turn instead of X. Because as you can see if i do X it will just always ask for X and not O. How can i make it choose to pull in X or O turn.
The problem is i need to only have one function that makes moves.
int main()
{
while(SOME CONDITION HERE)
{
printBoard();
cout << "Player X please choose a position: ";
makeMove('X');
cout << "Player O please choose a position: ";
makeMove('O');
}
}
int makeMove(char marker)
{
int choosePosition = 0;
cin >> choosePosition;
ticTacBoard[choosePosition - 1] = marker;
}
Start with this:
int main()
{
while(SOME CONDITION HERE)
{
printBoard();
cout << "Player X please choose a position: ";
makeMove('X');
cout << "Player O please choose a position: ";
makeMove('O');
}
}
int makeMove(char marker)
{
int choosePosition = 0;
cin >> choosePosition;
ticTacBoard[choosePosition - 1] = marker;
}
Note that you're going to want to change the SOME CONDITION HERE
part, but you could quickly replace it by 1
and get the same behavior of your current script (actually, a bit better).
But you'll eventually want to put something there that makes sense -- something that will tell the program to stop prompting the players for positions and, say, declare a winner.
The following is just a more streamlined way of doing the same thing:
int main()
{
while(SOME CONDITION HERE)
{
printBoard();
makeMove('X');
makeMove('O');
}
}
int makeMove(char marker)
{
cout << "Player " << marker << " please choose a position: ";
int choosePosition = 0;
cin >> choosePosition;
ticTacBoard[choosePosition - 1] = marker;
return 0;
}
Note the added return 0
-- if you don't want to return something, you should just make makeMove
return void
so as not to be confusing.