I see this in other people's code sometimes:
public void *foo() {
...
}
public void bar() {
...
}
but I never understood what the meaning of the *
was for, and if there is any difference between public void *foo()
and public void foo()
?
***This is C++ code here!
public void *foo()
is a public function that returns a void pointer (which can be anything essentially). More documentation on pointers can be found here: http://www.cplusplus.com/doc/tutorial/pointers/ (specifically the void pointer section).
public void *foo()
and public void* foo()
are the same and the position of *
is purely a style thing (although the style can have implications when used elsewhere).
public void foo()
is a public function that returns nothing.