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cmacrosc-preprocessorparentheses

C macros and use of arguments in parentheses

Example

#define Echo(a)  a
#define Echo(a) (a)

I realize there probably isn’t a significant difference here, but why would you ever want to include the a within parenthesis inside the macro body? How does it alter it?

Solution

  • Suppose you have

    #define mul(x, y)  x * y

    What happens if I say:

    mul(a + 5, 6); /* a + 5 * 6 */

    Now if I slighlty change the macro:

    #define mul(x, y)  ((x) * (y))
mul(a + 5, 6); /* ((a + 5) * (6)) */

    Remember, the arguments aren't evaluated or anything, only textual substitution is performed.

    EDIT

    For an explanation about having the entire macro in parentheses, see the link posted by Nate C-K.