i'm new to C - I have intended to make a program that shows whether the user input int
is odd
or even
, until the user decides to quit by inputing a char
'x
'. The loop kind of works by detecting odd numbers and terminating the program with 'x', however glitches with even numbers - why is that so? Would appreciate it if you could point out the flaws in the code. Thank you
#include <stdio.h>
int main(void)
{
int i=0;
char x = "x";
printf("Enter an integer to check whether your number is odd or even\n");
printf("Enter an ´x´ at any time to quit the program\n");
do
{
scanf("%d", &i);
if (i % 2 == 0)
{
printf("The number is even\n");
}
else if (i % 2 != 0)
{
printf("The number is odd\n");
}
else("%c ", &x);
{
scanf(" %c", &x);
getchar();
printf("The program will now terminate\n");
return 0;
}
}
while (i > 0);
i++;
return 0;
}
Very close but I've marked a couple of changes:
#include <stdio.h>
int main(void)
{
int i=0;
char x = 'x'; // Note: single quotes for char, double for string
printf("Enter an integer to check whether your number is odd or even\n");
printf("Enter an ´x´ at any time to quit the program\n");
do
{
int n = scanf("%d", &i); // Check if number was read
if (n == 1) {
if (i % 2 == 0)
{
printf("The number is even\n");
}
else // Only other possibility
{
printf("The number is odd\n");
}
} else // No number, see if there's an 'x'
{
scanf(" %c", &x);
if (x == 'x')
{
printf("The program will now terminate\n");
return 0;
} else
{
printf("Unknown input %c\n", x);
}
}
}
while (i > 0); // Will also end if user enters <= 0
return 0;
}