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expected-exception

expected expression before 'return' and '}' (curly brackets). I have tried changing everything, doesn't run

#include <stdio.h>
int main(){
    char a[5];
    for(char i = 0, i < 5, ++i){
        scanf("%c", &a[i]);
    }
    printf("%c", a[5]);
return 0;
}

I changed a[5] into a[i] in the printf, nothing changed. I have compared with this one i found on the net(which works ofc):

int main() {
  int values[5];
  for(int i = 0; i < 5; ++i) {
     scanf("%d", &values[i]);
  }
  for(int i = 0; i < 5; ++i) {
     printf("%d\n", values[i]);
  }
  return 0;
}
Solution

  • You are using , instead of semi colon ; in the for loop.

    for(char i = 0, i < 5, ++i)

    Correct Usage:

    for(char i = 0; i < 5; ++i)