How to return an int value in C?

Question

I am new to C language and trying to create a simple program to return name and age. I created a working function for returning the name but this does not work for returning the int.

The code I have now is:

int * GetAge(){  
  int Age;

  printf("What is your age: ");
  scanf(" %d", &Age);

  int * returnedage = Age;

  return returnedage;
}

This is GetName():

char * GetName(){
  char Name[31];

  printf("What is your name: ");
  scanf("%s", Name);

  char * returnedname = Name;

  return returnedname;
}

The warning is on this line:

int * returnedage = Age;

It says:

incompatible integer to pointer conversion
initializing 'int *' with an expression of type 'int'; take
the address with &

I have tried:

int * returnedage * Age;
int * returnedage & Age;
//for strcpy I set the function as a char
char * returnedage;
strcpy(Age, returnedage);

None of these work.

I want to just get the name and age then in main I am printing the name and age with:

printf("Your name is %s and your age is %d", GetName(), *GetAge());

This does not have any errors.

So my expected Output is:

What is your name: Ethan
What is your age: 13
Your name is Ethan and your age is 13

What I actually get is:

What is your name: ethan
What is your age: 13
exit status -1

Please tell me if there is a basic solution for this.

Answer 1

Change your code to this:

int GetAge()
{  
  int Age;

  printf("What is your age: ");
  scanf(" %d", &Age);

  return Age;
}

On main (Remove the * on the GetAge()):

printf("Your name is %s and your age is %d", GetName(), GetAge());

You have overcomplicated things. Read again the sources you are using to learn C to understand better what is going on.

Edited: Change your GetName() to:

void GetName(char *name){

  printf("What is your name: ");
  scanf("%s", name);
}

Now on main:

char name[31];
GetName(name);
printf("Your name is %s and your age is %d", name, GetAge());

The reason for that is that C can not return an array of characters (this is what you are trying to accomplish somehow). Instead, you can give that function the memory address of a local variable which lives in main() and store the user's input into that variable.