2D Dynamic array in C++

Question

If I declare a 2D dynamic array in C++ using the following code:

int *arr2D[2];              //allocating rows statically
for(int i=0;i<2;i++)
{
     arr2D[i]=new int[6];   //for each row, 6 columns are dynamically allocated
}

Then how should I enter and display values in this 2D dynamic array using loops? (issues with dynamic array traversal for entering and displaying values in it after its allocation)

Answer 1

You should use loops to input the array and display it:

int *arr2D[2];

for(int i = 0; i < 2; i++)
    arr2D[i] = new int[6];

for(int i = 0; i < 2; i++)
    for(int j(0); j < 6; j++){
        std::cout << "arr2D[" << i << "][" << j << "]: ";
        std::cin >> arr2D[i][j];
        std::cout << std::endl;
    }

for(int i = 0; i < 2; i++)
    for(int j(0); j < 6; j++){
        std::cout << "arr2D[" << i << "][" << j << "]: "
            << arr2D[i][j] << std::endl;
    }

Finally don't forget to free up memory (Memory allocated with new must be freed up by delete):

for(i = 0; i < 2; i++)
    delete[] arr2D[i];