Difference between func() and (*this).func() in C++

Question

I am working on someone else code in C++, and I found a weird call to a certain function func(). Here is an example:

if(condition)
    func();
else
    (*this).func();

What is the difference between func() and (*this).func()?

What are the cases where the call to func() and (*this).func() will execute different code?

In my case, func() is not a macro. It is a virtual function in the base class, with an implementation in both base and derived class, and no free func(). The if is located in a method in the base class.

Answer 1

There actually is a difference, but in a very non-trivial context. Consider this code:

void func ( )
{
    std::cout << "Free function" << std::endl;
}

template <typename Derived>
struct test : Derived
{
    void f ( )
    {
        func(); // 1
        this->func(); // 2
    }
};

struct derived
{
    void func ( )
    {
        std::cout << "Method" << std::endl;
    }
};

test<derived> t;

Now, if we call t.f(), the first line of test::f will invoke the free function func, while the second line will call derived::func.