How many bytes are dynamically allocated in the following code segment?

Question

Assuming that a memory address occupies 4 bytes and a char occupies 1 byte:

char** t;
t = malloc(5 * sizeof(char*));
int i;
for (i = 0; i < 5; i++)
 t[i] = malloc(sizeof(char) * (i+1));

Answer 1

35 bytes (Look below for breakup)

char** t;
t = malloc(5 * sizeof(char*));  // 5 * 4 = 20 bytes
int i;
for (i = 0; i < 5; i++)
 t[i] = malloc(sizeof(char) * (i+1)); //1 + 2 + 3 + 4 + 5 = 15 bytes