My config:
I have this method:
static inline std::u16string StringtoU16(const std::string &str) {
const size_t si = strlen(str.c_str());
char16_t cstr[si+1];
memset(cstr, 0, (si+1)*sizeof(char16_t));
const char* constSTR = str.c_str();
mbstate_t mbs;
memset (&mbs, 0, sizeof (mbs));//set shift state to the initial state
size_t ret = mbrtoc16 (cstr, constSTR, si, &mbs);
std::u16string wstr(cstr);
return wstr;
}
I want a conversion between char to char16_T pretty much (via std::string and std::u16string to facilitate memory management) but regardless of the size of the input variable str, it will return the first character only. If str= "Hello" it will return "H". I am not sure what is wrong my my method. Value of ret is 1.
I didn't know mbrtoc16() can only handle one character at a time.. what a turtle. Here is then the code I generate, and works like a charm:
static inline std::u16string StringtoU16(const std::string &str) {
std::u16string wstr = u"";
char16_t c16str[3] = u"\0";
mbstate_t mbs;
for (const auto& it: str){
memset (&mbs, 0, sizeof (mbs));//set shift state to the initial state
memmove(c16str, u"\0\0\0", 3);
mbrtoc16 (c16str, &it, 3, &mbs);
wstr.append(std::u16string(c16str));
}//for
return wstr;
}
for its counterpart (when one way is needed, sooner or later the other way will be needed):
static inline std::string U16toString(const std::u16string &wstr) {
std::string str = "";
char cstr[3] = "\0";
mbstate_t mbs;
for (const auto& it: wstr){
memset (&mbs, 0, sizeof (mbs));//set shift state to the initial state
memmove(cstr, "\0\0\0", 3);
c16rtomb (cstr, it, &mbs);
str.append(std::string(cstr));
}//for
return str;
}
Be aware that c16rtomb will be lossy if a character cannot be converted from char16_t to char (might endup printing a bunch of '?' depending on your system) but it will work without complains.