Pass 3D dynamically allocated array into function (C++)

Question

I have dynamically allocated a 3D array. I then assigned strings into the array. The 3D array prints out fine. But I cannot seem to find a way to pass it to a function. I have tried many variations of passing the array into the function. Below is my code, very grateful for any help.

//dynamically allocate 3d array
string *** array3D;
array3D = new string**[rows];
for(int i = 0; i < rows; i++)
{
    array3D[i] = new string*[columns];
    for(int j=0; j < columns;j++)
    {
        array3D[i][j] = new string[pages];
    }
}

//put strings from file into array
for(int k = 0; k < pages; k++)
{
    for(int i = 0; i < rows; i++)
    {
        for(int j=0; j < columns;j++)
        {
            puzzleFile >> array3D[i][j][k];
        }
    }
}

// Call function
find(array3D);

// The couts are simply to verify the array passed in successfully
void find(string ***&array)
{
    cout << "in function array[0][0][0]" << array[0][0][0] << endl;
    cout << "array[1][0][2]" << array[1][0][2] << endl;
    cout << "array[1][0][2]" << array[0][2][1] << endl;
    return;
}

Answer 1

Try to use rename function find with something else like myfind.

After discussing with OP, came to know he missed to declare function prototype. Hence updating answer.

Edit: Removed string.h include suggestion.