I never read anything about dereferencing arrays like pointers and I believe it shouldn't work. But the following code does work using QT Creator and g++ 4.8:
int ar[9]{1,2,3,4,5,6,7,8,9};
cout << *ar << endl; //prints the first element of ar
Is it proper behavior or just the compiler fixing the code?
You cannot dereference an array, only a pointer.
What's happening here is that an expression of array type, in most contexts, is implicitly converted to ("decays" to) a pointer to the first element of the array object. So ar
"decays" to &ar[0]
; dereferencing that gives you the value of ar[0]
, which is an int
.
This recent answer of mine discusses this in some detail for C. The rules for C++ are similar, but C++ has a few more cases where the conversion does not occur (none of which happen in your code).