A member is defined as
std::shared_ptr<std::array<std::string, 6> > exit_to;
which points to additional data shared among others. When try to initiate the pointer "exit_to". The correct way is
node_knot.exit_to = std::make_shared<std::array<std::string, 6> >();
But it's in another file and I'd like to keep the pointer type consistent, something like this:
node_knot.exit_to = std::make_shared<decltype(*node_knot.exit_to)>();
But won't compile:
/usr/include/c++/4.6/bits/shared_ptr_base.h:798:54: error: '__p'
declared as a pointer to a reference of type
'std::array<std::basic_string<char>, 6> &'
__shared_ptr(const __shared_ptr<_Tp1, _Lp>& __r, _Tp* __p)
^ /usr/include/c++/4.6/bits/shared_ptr.h:93:31: note: in instantiation
of template class
'std::__shared_ptr<std::array<std::basic_string<char>, 6> &, 1>'
requested here
class shared_ptr : public __shared_ptr<_Tp>
^ ../node_booker.h:757:20: note: in
instantiation of template class
'std::shared_ptr<std::array<std::basic_string<char>, 6> &>' requested
here
n.exit_to = std::make_shared<decltype(*n.exit_to)>();
I'm under Ubuntu 12.10, clang++ 3.2, with --std=c++11
You need to remove the reference from the type you are passing to make_shared.
The following should work:
node_knot.exit_to = std::make_shared<std::remove_reference<decltype(*node_knot.exit_to)>::type>();