In the following code snippet:
shared_ptr<int> p;
{
p = shared_ptr<int>(new int);
cout<<p.use_count()<<endl;
}
cout<<p.use_count()<<endl;
The output comes out to be
1 1
I don't understand why the 1st output is 1
-- shouldn't it be 2
?
The temporary object's lifetime does not last long enough for the first p.use_count()
to return 2. The temporary object is destroyed first, relinquishing its ownership on anything it owned.
Furthermore, since the temporary is an rvalue, the assignment to p
will result in a move-assignment, which means the use-count will never be 2 anyway (assuming a quality implementation). Ownership is simply transferred from the temporary to p
, never exceeding 1.