I am making a dictionary , keys having 2 words. Suppose I have two items in the dictionary:
{('am', 'and'): 1, ('and', 'am'): 1}
How to identify those above 2 keys are equal (they are just in different order).
for word1 in window:
for word2 in window:
if word1 != word2:
word_pair_freq[(word1, word2)] += 1
I want the result
{('am', 'and'): 2}
You can sort the tuples to detect duplicate pairs:
my_dict = {('am', 'and'): 1, ('and', 'am'): 1}
word_pair_freq = {}
for words, value in my_dict.items():
key = tuple(sorted(words))
word_pair_freq[key] = word_pair_freq.get(key, 0) + value
print(word_pair_freq)
this will print
{('am', 'and'): 2}