SQL function to download rows with specific values only

I have duplicate IDs with different activities. To return all the IDs, but remove duplicates, and to return three new columns called email, phone call and appointment containing true if activity is (email(for email columns), phone call(for phone column), appointment(for appointment columns)), otherwise false.

What I have

ID	Activity
101	Email
101	Appointment
102	Campaign
103	Phone call
104	Appointment

SELECT id,

MAX(CASE WHEN activity='Phone Call' THEN TRUE ELSE FALSE END) AS PhoneCall, 
MAX(CASE WHEN activity='Appointment' THEN TRUE ELSE FALSE END) AS Appointment,
MAX(CASE WHEN activity='Email' THEN TRUE ELSE FALSE END) AS Email

| 104 | Campaign |

What I want

ID	Email	Appointment	Phone call
101	True	True	False
102	False	False	False
103	False	False	Ture
104	False	Ture	False

Solution

This should be what you are looking for

SELECT id, MAX(CASE WHEN activity='Email' THEN 'True' ELSE 'False' END) AS Email, MAX(CASE WHEN activity='Appointment' THEN 'True' ELSE 'False' END) AS Appointment, MAX(CASE WHEN activity='Phone Call' THEN 'True' ELSE 'False' END) AS 'Phone Call' FROM {your_table_name} GROUP BY id;