how can I print dynamic array in c++ I need explanation to this question

Question

This is the question my teacher gave me:

• Construct a structure Employee that consists of the following fields: ID, name, degree, age
• A function that creates an object (a variable of Employee type), fills it from the user the, then returns it.
• A function that receives an object (a variable of Employee type) and prints its fields.
• Inside the main function:
  • Ask the user to specify the number of employees.
  • Create a dynamic array of the size specified by the user for the employees.
  • Inside a loop, fill the array elements one at a time by calling the first function.
  • Inside another loop, print the array elements one at a time by calling the second function.

I tried to solve it although I didn't understand it and this is what I have, Pleas help:

struct Employee
{
    int ID;
    char name[10];
    char degree;
    int age;

};

int fillin()
{   Employee employee;
    cout<<"Enter employee ID, NAME, DEGREE and AGE:\n";
    cin>>employee.ID;
    cin>>employee.name;
    cin>>employee.degree;
    cin>>employee.age;

}

int print()
{
    Employee employee;
    cout<<"ID: "<< employee.ID<<" , ";
    cout<<"NAME: "<< employee.name<<" , ";
    cout<<"Degree: "<< employee.degree<<" , ";
    cout<<"AGE: "<< employee.age<<".\n ";
}

int main()
{
    int num;
    cout<<"Enter number of employees: ";
    cin>> num;

   string *name= new string[num];

    for(int i = 0; i < num;i++)
    {
      name[i]=fillin();
    }


    for(int j : name){
        print();
    }
    return 0;
}

Answer 1

A function can have parameters and return a value. So here, fillin should return an Employee object, and print should take an Employee (or better a const reference) parameter:

Employee fillin()
{   Employee employee;
    cout<<"Enter employee ID, NAME, DEGREE and AGE:\n";
    cin>>employee.ID;
    cin>>employee.name;
    cin>>employee.degree;
    cin>>employee.age;
    return employee;      // return the local object
}

void print(const Employee& employee)
{
    cout<<"ID: "<< employee.ID<<" , ";
    cout<<"NAME: "<< employee.name<<" , ";
    cout<<"Degree: "<< employee.degree<<" , ";
    cout<<"AGE: "<< employee.age<<".\n ";
}

Your main function could become:

int main()
{
    int num;
    cout<<"Enter number of employees: ";
    cin>> num;

   Employee *name= new Employee[num];

    for(int i = 0; i < num;i++)
    {
      name[i]=fillin();
    }


    for(int i=0; i<num; i++){
        print(name[i]);
    }
    return 0;
}

Of course, you should check that the input methods return valid values (check cin after each read)