Can two floating point values (IEEE 754 binary64) be compared as integers? Eg.
long long a = * (long long *) ptr_to_double1,
b = * (long long *) ptr_to_double2;
if (a < b) {...}
assuming the size of long long
and double
is the same.
No. Two floating point values (IEEE 754 binary64) cannot compare simply as integers with if (a < b)
.
The order of the values of double
is not the same order as integers (unless you are are on a rare sign-magnitude machine). Think positive vs. negative numbers.
double
has values like 0.0
and -0.0
which have the same value but different bit patterns.
double
has "Not-a-number"s that do not compare like their binary equivalent integer representation.
If both the double
values were x > 0
and not "Not-a-number", endian, aliasing, and alignment, etc. were not an issue, OP's idea would work.
Alternatively, a more complex if() ...
condition would work - see below
[non-IEEE 754 binary64]
Some double
use an encoding where there are multiple representations of the same value. This would differ from an "integer" compare.
Tested code: needs 2's complement, same endian for double
and the integers, does not account for NaN.
int compare(double a, double b) {
union {
double d;
int64_t i64;
uint64_t u64;
} ua, ub;
ua.d = a;
ub.d = b;
// Cope with -0.0 right away
if (ua.u64 == 0x8000000000000000) ua.u64 = 0;
if (ub.u64 == 0x8000000000000000) ub.u64 = 0;
// Signs differ?
if ((ua.i64 < 0) != (ub.i64 < 0)) {
return ua.i64 >= 0 ? 1 : -1;
}
// If numbers are negative
if (ua.i64 < 0) {
ua.u64 = -ua.u64;
ub.u64 = -ub.u64;
}
return (ua.u64 > ub.u64) - (ua.u64 < ub.u64);
}
Thanks to @David C. Rankin for a correction.
Test code
void testcmp(double a, double b) {
int t1 = (a > b) - (a < b);
int t2 = compare(a, b);
if (t1 != t2) {
printf("%le %le %d %d\n", a, b, t1, t2);
}
}
#include <float.h>
void testcmps() {
// Various interesting `double`
static const double a[] = {
-1.0 / 0.0, -DBL_MAX, -1.0, -DBL_MIN, -0.0,
+0.0, DBL_MIN, 1.0, DBL_MAX, +1.0 / 0.0 };
int n = sizeof a / sizeof a[0];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
testcmp(a[i], a[j]);
}
}
puts("!");
}