Using PHP 5.3.5. Not sure how this works on other versions.
I'm confused about using strings that hold numbers, e.g., '0x4B0'
or '1.2e3'
. The way how PHP works with such strings seems inconsistent to me. Is it only me? Or is it a bug? Or undocumented feature? Or am I just missing some magic sentence in docs?
<?php
echo $str = '0x4B0', PHP_EOL;
echo "is_numeric() -> ", var_dump(is_numeric($str)); // bool(true)
echo "*1 -> ", var_dump($str * 1); // int(1200)
echo "(int) -> ", var_dump((int)$str); // int(0)
echo "(float) -> ", var_dump((float)$str); // float(0)
echo PHP_EOL;
echo $str = '1.2e3', PHP_EOL;
echo "is_numeric() -> ", var_dump(is_numeric($str)); // bool(true)
echo "*1 -> ", var_dump($str * 1); // float(1200)
echo "(int) -> ", var_dump((int)$str); // int(1)
echo "(float) -> ", var_dump((float)$str); // float(1200)
echo PHP_EOL;
In both cases, is_numeric()
returns true
. Also, in both cases, $str * 1
parses string and returns valid number (integer in one case, float in another case).
Casting with (int)$str
and (float)$str
gives unexpected results.
(int)$str
in any case is able to parse only digits, with optional "+" or "-" in front of them.(float)$str
is more advanced and can parse something like ^[+-]?\d*(\.\d*)?(e[+-]?\d*)?
, i.e., optional "+" or "-", followed by optional digits, followed by optional decimal point with optional digits, followed by optional exponent which consists of "e" with optional "+" or "-" followed by optional digits. Fails on hex data though.Related docs:
$str * 1
, but not with casting. Why?$s * 10
and (int)$s * 10
expressions to work the same way and to return the same result. Though, as shown in example, those expressions are evaluated differently.1.2e3
is valid numeric data. Sign ("+" or "-") is not mentioned. It does not mention hexidecimal values. This conflicts with definition of "numeric data" used in is_numeric()
. Then, there is suggestion "For more information on this conversion, see the Unix manual page for strtod(3)", and man strtod
describes additional numeric values (including HEX notation). So, after reading this, is hexidecimal data supposed to be valid or invalid numeric data?So...
is_numeric()
and the way how PHP treats strings when they are used as numbers?(int)$s
, (float)$s
and $s * 1
work differently, i.e,. give completely different results, when $s
is 0x4B0
or 1.2e3
?0x4B0
or as 1.2e3
? floatval()
does not work with HEX at all, intval()
needs $base
to be set to 16
to work with HEX, typecasting with (int)$str
and (float)$str
sometimes works, sometimes does not work, so these are not valid options. I'm also not considering $n *= 1;
, as it looks more like data manipulation rather than converting. Self-written functions also are not considered in this case, as I'm looking for native solution.The direct casts (int)$str
and (float)$str
don't really work differently at all: They both read as many characters from the string as they can interpret as a number of the respective type.
For "0x4B0", the int-conversion reads "0" (OK), then "x" and stops, because it cannot convert "x" into an integer. Likewise for the float-conversion.
For "1.2e3", the int-conversion reads "1" (OK), then "." and stops. The float-conversion recognises the entire string as valid float notation.
The automatic type recognition for an expression like $str * 1
is simply more flexible than the explicit casts. The explicit casts require the integers and floats to be in the format produced by %i
and %f
in printf
, essentially.
Perhaps you can use intval and floatval rather than explicit casts-to-int for more flexibility, though.
Finally, your question "is hexidecimal data supposed to be valid or invalid numeric data?" is awkward. There is no such thing as "hexadecimal data". Hexadecimal is just a number base. What you can do is take a string like "4B0" and use [Sorry, that was BS. There's no strtoul
etc. to parse it as an integer in any number base between 2 and 36.strtoul
in PHP. But intval
has the equivalent functionality, see above.]