How can PHP pull the JSON data from VIMEO API and print it on XML file?

I am calling the following Vimeo API to return all the videos under the specific videos. What I was trying to achieve is to only pull the particular JSON data that I desire to. "uri" and "name" is the only data that i need. And how can I print this thing to a XML file? https://developer.vimeo.com/api/reference/folders#get_project_videos

BTW this is my attempt:

<!DOCTYPE html>
<html lang="en" dir="ltr">
  <head>
    <meta charset="utf-8">
    <title></title>
  </head>
  <body>
      <?PHP

      header('Content-Type: text/html; charset=utf-8');
      require ("vendor/autoload.php");
      use Vimeo\Vimeo;

      $client = new Vimeo("{client_id}", "{client_secret}", "{access_token}");

      $user_id = '121265018';
      $project_id = '2370434';
      $response = $client- 
      >request("/users/$user_id/projects/$project_id/videos");

   var_dump($response);
   if ($response['status'] === 200) {
   $videos = [];
   foreach ($response['data'] as $data) {
     $result = [
       //'uri' => $data['uri'],
       'name' => $data['name'],
       //'pictures' => $data['pictures'],
     ];
     $videos[] = $result;
   }

   echo json_encode($videos, JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);
  } else {
    echo json_encode($response['body']['error']);
  }


   ?>

Solution

You just need to save the three things in a separate array and then print at the format that you want.

UPDATE

you have an array of data with all your videos. sow you need to use a foreach to get uri, name and pictures of all videos and save in another array.

<body>
  <?PHP
  header('Content-Type: text/html; charset=utf-8');
  require("vendor/autoload.php");

  use Vimeo\Vimeo;


  $client = new Vimeo("{client_id}", "{client_secret}", "{access_token}");

  $user_id = '121265018';
  $project_id = '2370434';
  $response = $client->request("/users/$user_id/projects/$project_id/videos");
  if ($response['status'] === 200) {
    $videos = [];
    foreach ($response['body']['data'] as $data) {
      $result = [
        'uri' => $data['uri'],
        'name' => $data['name'],
        'pictures' => $data['pictures'],
      ];
      $videos[] = $result;
    }

    echo json_encode($videos, JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);
  } else {
    echo json_encode($response['body']['error']);
  }
  ?>
</body>