Small program that uses pointers to sum integers

Question

I need to create a program which calculates the cumulative sum of a dynamically allocated vector and the vector should be filled with random values (not values from stdin) ​​using only pointers. I couldn't think of a version that uses only pointers (i'm kinda new to this matter).

This is the code I have so far:

#include <stdio.h>
#include <malloc.h>

int main()
{
    int i, n, sum = 0;
    int *a;

    printf("Define size of your array A \n");
    scanf("%d", &n);

    a = (int *)malloc(n * sizeof(int));
    printf("Add the elements: \n");

    for (i = 0; i < n; i++)
    {
        scanf("%d", a + i);
    }
    for (i = 0; i < n; i++)
    {
        sum = sum + *(a + i);
    }

    printf("Sum of all the elements in the array = %d\n", sum);
    return 0;
}

Answer 1

It's not something that much more complicated, instead of declaring int variables you need to declare int pointers and then allocate memory for them.

Something like:

Running sample

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int *n = malloc(sizeof(int)); //memory allocation for needed variables
    int *sum = malloc(sizeof(int));
    int *a;

    srand(time(NULL)); //seed

    printf("Define size of your array A \n");
    scanf("%d", n);

    if (*n < 1) {                  //size must be > 0
        puts("Invalid size");
        return 1;
    }

    printf("Generating random values... \n");
    a = malloc(sizeof(int) * *n); //allocating array of ints
    *sum = 0;                     //reseting sum

    while ((*n)--) {
        a[*n] = rand() % 1000 + 1; // adding random numbers to the array from 1 to 1000
        //scanf("%d", &a[*n]); //storing values in the array from stdin
        *sum += a[*n];       // adding values in sum
    }

    printf("Sum of all the elements in the array = %d\n", *sum);
    return 0;
}

EDIT

Added random number generation instead of stdin values