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c++stringc++11language-lawyernull-terminated

Is std::string always null-terminated in C++11?


In a 2008 post on his site, Herb Sutter states the following:

There is an active proposal to tighten this up further in C++0x and require null-termination and possibly ban copy-on-write implementations, for concurrency-related reasons. Here’s the paper: http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2008/n2534.html . I think that one or both of the proposals in this paper is likely to be adopted, but we’ll see at the next meeting or two.

I know that C++11 now guarantees that the std::string contents get stored contiguously, but did they adopt the above in the final draft?

Will it now be safe to use something like &str[0]?


Solution

  • Yes, per [string.accessors] p1, std::basic_string::c_str():

    Returns: A pointer p such that p + i == &operator[](i) for each i in [0,size()].

    Complexity: constant time.

    Requires: The program shall not alter any of the values stored in the character array.

    This means that given a string s, the pointer returned by s.c_str() must be the same as the address of the initial character in the string (&s[0]).