I am asked to use SFiNAE to reject non-integral versions of my Pow(T)
template function. So if the type deduced is an integral then return argument * argument
otherwise do nothing and just inform that the version has been rejected by SFINAE.
Here is my try:
template<typename T>
auto Pow(T x)->std::enable_if_t<std::is_integral<T>::value>
{
return x * x;
}
void Pow(...)
{
std::cout << "rejected by SFiNAE" << std::endl;
}
int main()
{
auto ret = Pow(5); // error here: 'ret': variable cannot have the type 'void'
cout << typeid(Pow(5)).name() << endl; // void
}
You need to provide the second parameter to std::enable_if
:
template<typename T>
auto Pow(T x)->std::enable_if_t<std::is_integral<T>::value, decltype(x * x)>
{
return x * x;
}