I want to find difference between list of dates in days.
I have a list of Timestamp object.
[Timestamp('2016-10-18 00:00:00'), Timestamp('2016-10-18 00:00:00'), Timestamp('2016-10-19 00:00:00'), Timestamp('2016-10-29 00:00:00'), Timestamp('2016-10-31 00:00:00'), Timestamp('2016-11-01 00:00:00'), Timestamp('2016-11-09 00:00:00'), Timestamp('2016-11-09 00:00:00'), Timestamp('2016-11-11 00:00:00'), Timestamp('2016-11-13 00:00:00'), Timestamp('2016-11-13 00:00:00')]
And I want the following result
[0,1,10,2,1,8,0,2,2,0]
I tried the following code but I am getting compilation error "TypeError: 'Timestamp' object is not iterable"
def calculateInterOrderTime(dateList):
result = map(lambda x: [i / np.timedelta64(1, 'D') for i in np.diff([c for c in x])[0]],dateList)
print(list(result))
It will be great if someone can help me with my lambda expression to do what I want.
Use Series
constructor, Series.diff
, Series.dt.days
, remove first value by Series.iloc
, convert to integers and then to lists:
print (pd.Series(dateList).diff().dt.days.iloc[1:].astype(int).tolist())
[0, 1, 10, 2, 1, 8, 0, 2, 2, 0]
Your solution should be changed with DatetimeIndex
, so is possible divide all values without list comprehension:
print ((np.diff(pd.DatetimeIndex(dateList)) / np.timedelta64(1, 'D')).astype(int).tolist())
[0, 1, 10, 2, 1, 8, 0, 2, 2, 0]