I am Working with the Jvector Map, In that I want to find the Country Code based on the Countries That I have in database as String.
For eg. IF the Country in Database is 'Australia' it should automatically convert it into its Country Code 'AU'
Suppose I recieved Multiple Country Names it should Automatically convert all the names to Country Codes at Once.
I Have an Associated Array of the Country Names With Country Codes , For eg.
$keyvalue =
array("Bangladesh"=>"BD",
"Belgium"=>"BE",
"Burkina Faso"=>"BF",
"Bulgaria"=>"BG",
"Bosnia and Herz"=>"BA",
"Brunei"=>"BN",
"Bolivia"=>"BO",
"Japan"=>"JP",
"Burundi"=>"BI", );
As I have all the country Codes stored in static array. How Can I match them with the Country Names I fetched From The Database.
I Have Tried the following php Code :
<?php
$query = "SELECT user_country FROM users" ;
$result = mysqli_query($conn,$query) ;
foreach($keyvalue as $x => $x_value) {
"Key=" . $x . ", Value=" . $x_value;
"<br>";
}
foreach($result as $rec => $x_value)
{
echo $rec['user_country'] ." : " . $rec[$x_value];
}
?>
I Hope My Question is Clear. What Am I Missing and How Can I persue this particular problem. Pardon my code, it may have multiple flaws in it
I suppose you just want to echo them judging from your second loop, in that case you can use
$keyvalue = //your array here;
$query = "SELECT user_country FROM users" ;
$result = mysqli_query($conn,$query) ;
echo "<table>";
echo "<tr><th>Country</th><th>Country Code</th></tr>";
while($row = mysqli_fetch_assoc($result)){
echo "<tr> ";
echo "<td>" . $row['user_country'] . "</td>";
echo "<td>" . $keyvalue[$row['user_country']] . "</td>";
}
echo "</table>";