How to Loop Through a const char**?

Question

I have a const char** called glfwNames which holds the C version of a string array of the required GLFW library extensions. Would it be possible to loop through either the const char* (string), or the individual characters of the string separated by '\0'?

    const char** glfwNames = glfwGetRequiredInstanceExtensions(&glfwCount)

    for (const char** name = glfwNames; *name; ++name)
    {
         slog("GLFW Extensions to use: %s", *name);
    }

This is what I've attempted from one of the answers, and the return value of

glfwGetRequiredInstanceExtensions

is an array of extension names, required by GLFW http://www.glfw.org/docs/latest/group__vulkan.html#ga1abcbe61033958f22f63ef82008874b1

Answer 1

If glfwNames is nullptr-terminated:

#include <cstdio>

int main()
{
    char const *glfwNames[] = { "foo", "bar", "baz", nullptr };
    for (char const **p = glfwNames; *p; ++p)
        std::puts(*p);
}

If you *know* the number of strings:

std::uint32_t glfwCount;
const char** glfwNames = glfwGetRequiredInstanceExtensions(&glfwCount)

for (std::uint32_t i{}; i < glfwCount; ++i)
{
     slog("GLFW Extensions to use: %s", glfwNames[i]);
}

To also loop through the individual chars:

for (std::uint32_t i{}; i < glfwCount; ++i)
{
     for(char const *p{ glfwNames[i] }; *p; ++p)
         std::putchar(*p);
}