struct sigaction psa;
I have enabled my signal handler in the main function as shown below:
memset (&psa, 0, sizeof (psa));
psa.sa_handler = pSigHandler;
sigaction (SIGALRM, &psa, NULL);
sigaction(SIGVTALRM, &psa, NULL);
sigaction(SIGPROF, &psa, NULL);
My signal handler is like this:
static void pSigHandler(int signo){
printf("Pareint signum: %d", signo);// debug
switch (signo) {
case SIGALRM:
printf("P SIGALRM handler");//debug
break;
case SIGVTALRM:
printf("P SIGVTALRM handler");//debug
break;
case SIGPROF:
printf("P SIGPROF handler");//debug
break;
default: /*Should never get this case*/
break;
}
return;
}
Now my question may be obvious to some people, why didn't I see the printed debug lines when I run this? In fact, nothing was printed. Thank you very much for helping me to understand this. I'm running it on Linux, used Eclipse to program.
#include <stdio.h>
#include <signal.h>
static void pSigHandler(int signo){
switch (signo) {
case SIGTSTP:
printf("TSTP");
fflush(stdout);
break;
}
}
int main(void)
{
struct sigaction psa;
psa.sa_handler = pSigHandler;
sigaction(SIGTSTP, &psa, NULL);
for(;;) {}
return 0;
}
Because you need to fflush(stdout)
try with C-z
I'm not even sure if it's safe to use stdio in a signal handler though.
Update: http://bytes.com/topic/c/answers/440109-signal-handler-sigsegv
According to that link, you should not do this.