How to initialize the loop counter declared with the auto keyword?

Question

Here is my code:

#include <iostream>
#include <vector>

void cumulative_sum_with_decay(std::vector<double>& v)
{
    for (auto i = 2; i < v.size(); i++) {
        v[i] = 0.167 * v[i - 2] + 0.333 * v[i - 1] + 0.5 * v[i];
    }
}

void printv(std::vector<double>& v)
{
    std::cout << "{";
    for (auto i = 0; i < v.size() - 1; i++) {
        std::cout << i << ", ";
    }
    std::cout << v[v.size() - 1] << "}\n";
}

int main()
{
    auto v = std::vector<double>{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    cumulative_sum_with_decay(v);
    printv(v);
}

When I try to compile and run this program, I get these warnings:

$ clang++ -std=c++11 -Wextra foo.cpp && ./a.out
foo.cpp:6:24: warning: comparison of integers of different signs: 'int' and 'std::__1::vector<double,
      std::__1::allocator<double> >::size_type' (aka 'unsigned long') [-Wsign-compare]
    for (auto i = 2; i < v.size(); i++) {
                     ~ ^ ~~~~~~~~
foo.cpp:14:24: warning: comparison of integers of different signs: 'int' and 'unsigned long'
      [-Wsign-compare]
    for (auto i = 0; i < v.size() - 1; i++) {
                     ~ ^ ~~~~~~~~~~~~
2 warnings generated.
{0, 1, 2, 3, 4, 5, 6, 7, 8, 8.68781}

How can I initialize these loop counters declared with auto such that the code is safe and there are no warnings?

Note that although I have a small vector here, I am trying to learn how to write safe code with auto even when the vector is so large that the value in i can exceed the range of integers.

Answer 1

The type of auto-declared variable is deduced from the initializer. given 2 or 0 it'll be int.

You could specify the type with explicitly typed initializer. e.g.

for (auto i = static_cast<decltype(v.size())>(2); i < v.size(); i++) {