What will be printed for A
and B
in the second $display
statement?
module blocking;
reg[0:7] A, B;
initial begin
A = 3;
#1 A = A + 1;
B = A + 1;
$display("Blocking: A= %d B= %d", A, B ); // A = 4, B = 5
A = 3;
#1 A <= A + 1;
B <= A + 1;
#1 $display("Non-blocking: A= %d B= %d", A, B ); // A = ?, B = ?
end
endmodule
How does event scheduling in Verilog work with respect to delays and non-blocking statements?
Because you have #1
before the second $display
statement, it will be executed in the next cycle after A
and B
are settled.
Say we are at cycle #1.
A = 3; // at #1
#1 // (does not matter) --> #2
A <= A + 1; // #2 will do A + 1 and wait till the end of the cycle
B <= A + 1; // #2 same as above
// at the end of the cycle #2 (nba scheduling bucket) before switching to #3
// A and B will be assigned '4'
#1 // --> #3
// new values of A and B are available here (4)
$display("Non-blocking: A= %d B= %d", A, B );