I am trying to compile an assembler-based implementation of AES, viewable here. My assembler is giving me the following error, repeated several different times over what appear to be instances of the same error. The exact source location is here, but due to the large amount of preprocessor indirection used in this file, I have copied the exact error from my build output, which gives the exact code as seen by the compiler:
/Volumes/Sources/Andromeda/Kernel/libkern/crypto/aes/EncryptDecrypt.s:297:19: error: invalid operand for instruction
movzx 240(%r10), %rax
^~~~
I do not quite understand what may be causing this problem. If I understand it properly, this instruction moves a byte (or more, this is unclear, and may in fact be the source of the problem) into the RAX register, zero-extending it if the source is less than 64-bits in size. Do I need to explicitly specify a size by adding a tag to the movxz instruction (e.g. movzxb)? What else might be the cause of this problem? Thanks!
At&t syntax does not normally use movzx, but maybe some assembler versions accept it. My copy of GNU assembler 2.22 does, but maybe OSX version doesn't. In any case, the assembler generates code for a byte source. If you do in fact have that, the proper at&t syntax would be movzbq 240(%r10), %rax, or, taking advantage of automatic zero extension, movzbl 240(%r10), %eax.
If you have a 4 byte source, then you can't use movzx at all, since it does not exist for that operand type. All you need in this case is the automatic zero extension, so you can simply do movl 240(%r10), %eax.