I searched for a proper way to use the folderbrowserdialog
but i'm getting a warning and I don't get why.
I added the folderbrowserdialog on my form in the design window.
Then I used this code, like I found on various websites.
If (FolderBrowserDialog1.ShowDialog() = DialogResult.OK) Then
tb_CopyToPath.Text = FolderBrowserDialog1.SelectedPath
End If
And visual studio is giving me following warning.
BC42025
Access of shared member, constant member, enum member or nested type through an instance; qualifying expression will not be evaluated.
What do I need to change to remove this warning?
That warning is because you're inside a Form
(which has a DialogResult
property) and you're using DialogResult
enumeration (of which OK
is a Shared
member). Compiler is telling you that you're accessing a Shared
member (OK
, in this case) through an instance (DialogResult
property value, which by case is also of type DialogResult
).
AFAIK it has been solved long time ago but if you're using an old VB.NET compiler then you may still need to specify full type name (which will disambiguate between property and type name):
FolderBrowserDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK
Side comment about naming convention: pick a proper name for FolderBrowserDialog1
and do not use underscore in identifiers...