We have a feature that collects customer feedback. For this , when the user logs out , a window pops up up randomly - not every time for every customer. I want to handle this in my automation code.
Currently, at the log out, I'm expecting a window and switching to it and that code is failing when the popup window doesn't show up.
What's the best way to handle this .
This is what I have so far ...
public static void waitForNumberOfWindowsToEqual(final int numberOfWindows) {
ExpectedCondition<Boolean> expectation = new ExpectedCondition<Boolean>() {
public Boolean apply(WebDriver driver) {
return (driver.getWindowHandles().size() == numberOfWindows);
}
};
WebDriverWait wait = new WebDriverWait(driver, BrowserFactory.explicitWait);
wait.until(expectation);
}
I would handle the absence of popup window with a try/catch. Here is an example:
try {
WebDriverWait winwait = new WebDriverWait(driver, 3);
String mainWindow = driver.getWindowHandle();
// wait for 2 windows and get the handles
Set<String> handles = winwait.until((WebDriver drv) -> {
Set<String> items = drv.getWindowHandles();
return items.size() == 2 ? items : null;
});
// set the context on the last opened window
handles.remove(mainWindow);
driver.switchTo().window(handles.iterator().next());
// close the window
driver.close();
// set the context back to the main window
driver.switchTo().window(mainWindow);
} catch (TimeoutException ex) {
System.out.println("No window present within 3 seconds");
}