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scalaplayframeworkanorm

Convert result set to Seq[(String,String)] using Scala and anorm in play


I have tried to get result set from mySQL database table using anorm. here is my code.

package models
import play.api.db._
import play.api.Play.current
import scala.collection.mutable._
import anorm._
import anorm.SqlParser._

    case class Brand(id: Int, name: String)


        object Brand {

             /**
            * Parse a Brand from a ResultSet
            */
            val simple = {
                get[Int]("m_brand.idbrand") ~
                get[String]("m_brand.brandName") map {
                case id~name => Brand(id, name)
                }
            }

            /**
            * Construct the Map[String,String] needed to fill a select options set.
            */
            def options: Seq[(String,String)] = DB.withConnection { implicit connection =>
                 SQL("select * from m_brand order by brandName").as(Brand.simple *).
                    foldLeft[Seq[(String, String)]](Nil) { (cs, c) => 
                     c.id.fold(cs) { id => cs :+ (id.toString -> c.name) }
                }
            }

} 

I tried change code with some experiments but not worked.

But I got this error

Read from stdout: D:\PROJECTS\test\Project_VendorM8\app\models\Brand.scala:69: type mismatch; Read from stdout: found : scala.collection.immutable.Nil.type Read from stdout: required: scala.collection.mutable.Seq[(String, String)] D:\PROJECTS\test\Project_VendorM8\app\models\Brand.scala:69: type mismatch; found : scala.collection.immutable.Nil.type required: scala.collection.mutable.Seq[(String, String)] Read from stdout: foldLeftSeq[(String, String)] { (cs, c) => foldLeftSeq[(String, String)] { (cs, c) => Read from stdout: ^


Solution

  • As asked in the comments, would a simpler solution not be just to use map and write:

    def options: Seq[(String,String)] = DB.withConnection { implicit connection =>
      SQL("select * from m_brand order by brandName").as(simple *)
        .map( b => (b.id.toString, b.name))
        .toSeq
    }