What's the most concise way to determine if @hash[:key1][:key2]
is defined, that does not throw an error if @hash
or @hash[:key1]
are nil?
defined?(@hash[:key1][:key2])
returns True if @hash[:key1]
exists (it does not determine whether :key2
is defined)
When using ActiveSupport (Rails) or Backports, you can use try
:
@hash[:key1].try(:fetch, :key2)
You could even handle @hash
being nil
:
@hash.try(:fetch, :key1).try(:fetch, :key2)
If you want @hash
to always return a hash for a missing key:
@hash = Hash.new { |h,k| h[k] = {} }
@hash[:foo] # => {}
You could also define this recursive:
def recursive_hash
Hash.new { |h,k| h[k] = recursive_hash }
end
@hash = recursive_hash
@hash[:foo][:bar][:blah] = 10
@hash # => {:foo => {:bar => {:blah => 10}}}
But to answer your question:
module HasNestedKey
Hash.send(:include, self)
def has_nested_key?(*args)
return false unless sub = self[args.shift]
return true if args.empty?
sub.respond_to?(:has_nested_key?) and sub.has_nested_key?(*args)
end
end
@hash.has_nested_key? :key1, :key2