Given a list of inputs that could be valid or invalid, is there a nice way to transform the list but to fail given one or more invalid inputs and, if necessary, to return information about those invalid inputs? I have something like this, but it feels very inelegant.
def processInput(inputList: List[Input]): Try[List[Output]] = {
inputList map { input =>
if (isValid(input)) Left(Output(input))
else Right(input)
} partition { result =>
result.isLeft
} match {
case (valids, Nil) =>
val outputList = valids map { case Left(output) => output }
Success(outputList)
case (_, invalids) =>
val errList = invalids map { case Right(invalid) => invalid }
Failure(new Throwable(s"The following inputs were invalid: ${errList.mkString(",")}"))
}
}
Is there a better way to do this?
I think you can simplify your current solution quite a bit with standard scala:
def processInput(inputList: List[Input]): Try[List[Output]] =
inputList.partition(isValid) match {
case (valids, Nil) => Success(valids.map(Output))
case (_, invalids) => Failure(new Throwable(s"The following inputs were invalid: ${invalids.mkString(",")}"))
}
Or, you can have a quite elegant solution with scalactic
's Or
.
import org.scalactic._
def processInputs(inputList: List[Input]): List[Output] Or List[Input] =
inputList.partition(isValid) match {
case (valid, Nil) => Good(valid.map(Output))
case (_, invalid) => Bad(invalid)
}
The result is of type org.scalactic.Or
, which you then have to match to Good
or Bad
. This approach is more useful if you want the list of invalid inputs, you can match it out of Bad
.