I'm getting the error "The INSERT statement conflicted with the FOREIGN KEY constraint...." I have searched for similar problems but I cannot find the one that solves mine. Solution I've seen is that I dont have a record on the referenced table. (I have) but still does not work.
I have table called Parent
and ParentFeedback
which is referencing the Parent
table.
I have already created 2 records in Parent
. Now when I try to insert a ParentFeedback
record using my Insert statement
Insert into ParentFeedback
Values(@parentid, @feed, @date , @status)
I get an error (shown in the title).
I have made sure already that the parentid that I'm putting exists and I am able to grab it and put it in @parentid
.
But why am I still getting that error?
If you want to see it, Click here to be directed to the page.
just search for asdasd firstname and asdasd lastname then put a feedback and submit. asdasd is an existing record in Parent table with ID of 1. which I put for the parentid in my insert.
Hi Guys im really sorry to bother you, I thought that I was passing my parent ID properly but it turns out it aint giving me an ID and its always 0.