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c++c++11auto

C++ determine the type of auto and pass to function template

I have a function :

template<typename T> f(T x) { do something with x; }

I want to pass this auto pointer into the function

auto x = ...
f<???>(x)

Is there anyway for me to do so ?

Solution

  • Just call it like

    auto x = ...
f(x)

    templated functions automatically deduce the type depending on the arguments you pass it. In fact that's the preferred way to call a templated function.

    If you really want to explicitly give it the type (I don't recommend doing that) you can use decltype for it:

    auto x = ...
f<decltype(x)>(x)

    Here a minimal proof: http://coliru.stacked-crooked.com/a/d01070d90c0b9803