C:folding a line after a fixed column

Question

I am trying to write my solution for the KnR problem 1-22. Below is my code which I am not able to get why it's not working. It just prints the whole line that I typed, without folding.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SPACE ' '
#define LIMIT 1024
#define BREAK 20
#define ON 1
#define OFF 0

int main(void) {
    /*base, is an offset from where the difference of current array position will be calculated*/
    int c,base=0,i,l_break=OFF;
    char s[LIMIT];
    for(i = 0; (c = getchar()) != EOF; ++i) {
        /*If break is on and space comes, turn the space into newline so that the line folds*/
        if(l_break==ON && c==SPACE) {
            c=='\n';
            base=i;
        }
        /*Breaking position is reached but not a blank position yet to break.*/
        if(((i-base)==BREAK) && c!=SPACE)
            l_break=ON;
        /*If user sends a newline explicitly(or space converted to newline above), reset the base*/
        if(c == '\n') {
            base=i;
            s[i] = c;
            l_break=OFF;
        } else
            s[i] = c;
    }
    s[i] = '\0';
    /*Print the final sentence after processing*/
    i=0;
    printf("\n");
    while(s[i]!='\0') {
        printf("%c",s[i]);
        ++i;
    }
    printf("\n");
    return 0;
}

Also, when I send EOF (^D) it again comes to read ,then I need to send EOF again to break it off. Why its not breaking first time I send EOF.

Answer 1

c=='\n'; should be c = '\n'; - Haven't checked to ensure that is the only issue...