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pythonemailpython-2.7mod-wsgiwsgi

Python : How to parse the Body from a raw email , given that raw email does not have a "Body" tag or anything


It seems easy to get the

From
To
Subject

etc via

import email
b = email.message_from_string(a)
bbb = b['from']
ccc = b['to']

assuming that "a" is the raw-email string which looks something like this.

a = """From [email protected] Thu Jul 25 19:28:59 2013
Received: from a1.local.tld (localhost [127.0.0.1])
    by a1.local.tld (8.14.4/8.14.4) with ESMTP id r6Q2SxeQ003866
    for <[email protected]>; Thu, 25 Jul 2013 19:28:59 -0700
Received: (from root@localhost)
    by a1.local.tld (8.14.4/8.14.4/Submit) id r6Q2Sxbh003865;
    Thu, 25 Jul 2013 19:28:59 -0700
From: [email protected]
Subject: oooooooooooooooo
To: [email protected]
Cc: 
X-Originating-IP: 192.168.15.127
X-Mailer: Webmin 1.420
Message-Id: <1374805739.3861@a1>
Date: Thu, 25 Jul 2013 19:28:59 -0700 (PDT)
MIME-Version: 1.0
Content-Type: multipart/mixed; boundary="bound1374805739"

This is a multi-part message in MIME format.

--bound1374805739
Content-Type: text/plain
Content-Transfer-Encoding: 7bit

ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo

--bound1374805739--"""

THE QUESTION

how do you get the Body of this email via python ?

So far this is the only code i am aware of but i have yet to test it.

if email.is_multipart():
    for part in email.get_payload():
        print part.get_payload()
else:
    print email.get_payload()

is this the correct way ?

or maybe there is something simpler such as...

import email
b = email.message_from_string(a)
bbb = b['body']

?


Solution

  • Use Message.get_payload

    b = email.message_from_string(a)
    if b.is_multipart():
        for payload in b.get_payload():
            # if payload.is_multipart(): ...
            print payload.get_payload()
    else:
        print b.get_payload()