Creating 20,000 MAC addresses in a string vector

Question

I need to create a string vector of MAC addresses from 1000.1111.1111 to 1000.1131.1111 or a range similar to that.

I am not sure how to increment the string, or if I concatenate then how to maintain leading zeros.

Any pointers are appreciated.

Yes these are hex. Although I would not mind a solution that takes care of base 10 only.

Answer 1

This will generate a vector of strings like this:

1000.1111.1111
1000.1111.1112
1000.1111.1113
<...>
1000.1112.1111
1000.1112.1112
<...>
1000.1131.1111

---

Code:

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

//Converts a number (in this case, int) to a string
string convertInt(int number)
{
   stringstream ss;//create a stringstream
   ss << number;//add number to the stream
   return ss.str();//return a string with the contents of the stream
}

int main(int argc, char *argv[])
{
    //The result vector
    vector<string> result;
    string tmp;//The temporary item 
    for( int i = 1111; i < 1139; i++ )
        for( int j = 1111; j < 9999; j++ )
        {
            tmp = "1000.";//the base of the adress
            //Now we append the second and the third numbers.
            tmp.append( convertInt( i ) ).append( "." ).append( convertInt( j ) );
            //and add the tmp to the vector
            result.push_back(tmp);
        }
}