output of c code

Question

Why output is giving 3 , expecting -3. How to handle such preprocessing in c?

#include<stdio.h>
#include<math.h>
#define sq(x) ((x<0)?sqrt(-x):sqrt(x))

int main()
{
    int x;
    x=sq(-9);
    printf("%d\n",x);
    return 0;
}

Answer 1

because your # define "sq" checks if its a negative number and turns it into a positive number before calculating a square root

its doing sqrt(-x) which is sqrt(-(-9)) ( taking the negative of a negative is the positive)

so its doing sqrt(9)