C Programming: Name arranger! Coding newb?

Question

Complete newbie here. 2nd day in my intro to programming class, so be gentle. We're programming in C btw.

Our assignment was to prompt the user to give us a name in the format: John Smith, and then print it back out to them like so; Smith, J.

To add to the headache the program still has to perform regardless of how many blank spaces there are. i.e. John /n Smith, John /t smith, and John /0 Smith..

Here's what I have so far,

#include <stdio.h>

int input()
{
    printf("Enter your name: \n");
    int lettest = getchar ();
    return (lettest);
}

void fname() 
{
    int lettest;
    if (lettest != EOF || '\n' || '\t' || ' ')
    {
        printf("%c.", lettest);
        lettest = getchar();
    }
    else;
}
void lname() 
{
    int lettest;
    if (lettest != EOF || '\n' || '\t' || ' ')
    {
        printf("%c.", lettest);
        lettest = getchar();
    }
    else;
}

int main () {

    input();
    lname();
    //fflush(stdin);
    fname();

    return 0;
}

My problems: I don't know how to print the last name when it's reading both from the same buffer..

Can someone explain to me how I would do my lname function??? Also, no arraylists and no string methods.

Answer 1

Note that in addition to the problems mentioned in other answers, expressions such as:

if (lettest != EOF || '\n' || '\t' || ' ')

do not behave as you expect them to - you need to write this particular example as:

if (lettest != EOF && lettest != '\n' && lettest != '\t' && lettest !=  ' ')

or perhaps more expressively:

if (!(lettest == EOF || lettest == '\n' || lettest == '\t' || lettest ==  ' '))