How to validate xml with dtd using java?

Question

I have following xml file:

<?xml version = "1.0" ?>
<Employee>
    <Emp_Id>E-001</Emp_Id>
    <Emp_Name>Vinod</Emp_Name>
    <Emp_E-mail>Vinod1@yahoo.com</Emp_E-mail>
</Employee>

I have following dtd file:

<!ELEMENT Employee (Emp_Id, Emp_Name, Emp_E-mail)>
<!ELEMENT Emp_Id (#PCDATA)>
<!ELEMENT Emp_Name (#PCDATA)>
<!ELEMENT Emp_E-mail (#PCDATA)>

I want to validate this xml file with above dtd using java.

Please, help thanks..:-)

Answer 1

There are three things you should do:

• Associate the source XML document with its DTD using a doctype declaration after the XML declaration:

  <!DOCTYPE Employee SYSTEM "employee.dtd">
  

  Note: The DOCTYPE root must match the root element in the source XML.

• setValidating to true on the DocumentBuilderFactory

• Provide an org.xml.sax.ErrorHandler instance to the DocumentBuilder using setErrorHandler

Here's a complete example:

DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setValidating(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
builder.setErrorHandler(new ErrorHandler() {
    @Override
    public void error(SAXParseException exception) throws SAXException {
        // do something more useful in each of these handlers
        exception.printStackTrace();
    }
    @Override
    public void fatalError(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }

    @Override
    public void warning(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }
});
Document doc = builder.parse("employee.xml");

Source document:

<?xml version="1.0"?>
<!DOCTYPE Employee SYSTEM "employee.dtd">
<Employee>
    <Emp_Id> E-001</Emp_Id>
    <Emp_Name> Vinod </Emp_Name>
    <Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>