Mark constructor as __explicitly__ requiring an object type

Question

I have a constructor that accepts an object of type Material:

SomeClass::SomeClass( const Material& mat ) ;

However, Material allows construction by a Vector:

Material::Material( const Vector& v ) ;

Therefore, SomeClass can allow construction by a Vector:

SomeClass m( vec ) ; // valid, since vec is constructed to a Material first,
// then is passed to the SomeClass(Material) ctor

However, after "shooting myself in the foot" more than once with ctors of this type (in different classes in the same project!) I want to disallow construction of SomeClass by Vector objects directly, instead always requiring a Material to be passed instead.

Is there a way to do this? Somehow think it has to do with the explicit keyword.

Answer 1

You cannot do this without interfering with your ability to transparently construct Material from Vector.

If you make Material's constructor explicit

explicit Material( const Vector& v ) ;

then you will always have to write Material(v) in order to construct an instance. This will prevent you from instantiating SomeClass with a Vector accidentally, but it will also break all expressions that evaluate to a Vector where a Material is expected.

This makes sense, because by not declaring the constructor explicit you are saying "a Vector is just as good as a Material no matter what the context". You cannot then do a half-step backward and say "oh, well, except when constructing a SomeClass".