I have the following code which performs background subtraction and then uses findContours to draw a boundary around the foreground object.
// frame - Input frame from a camera.
// output - Output frame to be displayed.
void process(cv:: Mat &frame, cv:: Mat &output) {
cv::cvtColor(frame, gray, CV_BGR2GRAY);
// initialize background to 1st frame
if (background.empty())
gray.convertTo(background, CV_32F);
// convert background to 8U
background.convertTo(backImage,CV_8U);
// compute difference between current image and background
cv::absdiff(backImage,gray,foreground);
// apply threshold to foreground image
cv::threshold(foreground,output,threshold,255,cv::THRESH_BINARY_INV);
// accumulate background
cv::accumulateWeighted(gray, background, learningRate, output);
// Find regions of interest
std::vector<std::vector<cv::Point> > v; // Detected foreground points
cv::findContours(output,v,CV_RETR_LIST,CV_CHAIN_APPROX_NONE);
// Sort to find the entry with the most points at the beginning.
// This is done to overcome noisy input.
std::sort(v.begin(), v.end(), DescendingCompare);
cv::Mat drawing = frame;
std::vector<std::vector<cv::Point>> contours_poly(1);
// Determine an approximate polygon for v[0] which is the largest contour
cv::approxPolyDP( cv::Mat(v[0]), contours_poly[0], 3, false );
// Draw polygonal contour
cv::Scalar color = cv::Scalar( 0,0,255 );
cv::drawContours( drawing, contours_poly, 0, color, 2, 8, std::vector<cv::Vec4i>(), 0, cv::Point() );
// Show in a window
output = drawing;
v.clear();
}
The image is just a blank white background but findContours() is returning a contour with the 4 edges of the image. This ends up being the largest contour found, negating my logic in the code.Is there anyway to fix this ? I want it to return a null vector when the screen is blank.
Also, can this code be improved in anyway to improve efficiency ?
Your background should be black (0) and any object you want to contour should be white( or >= 1). You have it reversed and that's why FindContours detects the background as a contour and not the object.