C# - Calling function from another form

Question

I need a tray notify from another form. ControlPanel.cs (default form, notifyicon here):

  ...
  public partial class ControlPanel : Form
    {
        public string TrayP
        {
            get { return ""; }
            set { TrayPopup(value, "test");}

        }

   public void TrayPopup(string message, string title)
    {
        TrayIcon.BalloonTipText = message;
        TrayIcon.BalloonTipTitle = title;
        TrayIcon.ShowBalloonTip(1);
    }

Form1.cs (another form):

...
public partial class Form1 : Form
{

    public ControlPanel cp;
    ....

    private void mouse_Up(object sender, MouseEventArgs e) {
        cp.TrayP = "TRAY POPUP THIS";
    }

On line cp.TrayP = "TRAY POPUP THIS"; I am getting a NullException. If i change it to cp.TrayPopup("TRAY POPUT THIS", "test"); an exception throws whatever.

If i make this:

private void mouse_Up(object sender, MouseEventArgs e) {
    var CP = new ControlPanel();
    CP.TrayPopup("TRAY POPUP THIS", "test");
}

, tray popup shows, but it`s creates the second tray icon and then show balloon hint from new icon. What can I do? P.S.: Sorry for bad English.

Answer 1

If you are opening second form "Form1" from ControlPanel, you should pass the instance of CP to Form1, like

public partial class ControlPanel : Form
{

    public void ShowForm1(){
        FOrm1 f1 = new Form1();
        f1.SetCp(this);
        f1.show();
    }

    public void TrayPopup(string message, string title)
    {
        TrayIcon.BalloonTipText = message;
        TrayIcon.BalloonTipTitle = title;
        TrayIcon.ShowBalloonTip(1);
    }
}

public partial class Form1 : Form
{

    public ControlPanel _cp;
    public void SetCP(controlPanel cp){
            _cp = cp;
    }

    private void mouse_Up(object sender, MouseEventArgs e) {
            if(_cp != null)
            _cp.TrayPopup("TRAY POPUP THIS", "test");
    }
}