Get upper left corner position of the JPopupMenu object

Question

I have a JPopupMenu object. Its behavior depends on its coordinates. How can I get its position relatively to its parent container?

Answer 1

In your MouseListener's method (mouseReleased etc.) you should receive a MouseEvent object containing the current position. If you don't want to use those values you can try using the Component#getLocation method, otherwise the Component#getLocationOnScreen but it returns the absolute position, then you need to calculate the relative one.