Lambda function failing to call static functions of a function template parameter

Question

Ok, so I have something setup basically like this:

template<typename T> void example()
{
 std::function<int (byte*)> test = [=](byte* start) -> int
 {
  return T::magic(start);
 }
}

Ignoring how "unclean" making these naked calls is, it also doesn't compile, giving these errors:

'T' : is not a class or namespace name
'magic': identifier not found

Is there any way to be able to make a call on the generic typename T, assuming I will always be calling example() with a class that has the function magic(byte* start)? Surely I don't have to redeclare this template function for every single class that will be doing this.

I'm doing this in VC++ 2010, and it appears it may be a compiler bug. Any possible workarounds?

Answer 1

The only error there is the missing semi-colon. Once that is fixed, it works fine.

#include <iostream>
#include <functional>

typedef unsigned char byte;

template<typename T> void example()
{
    std::function<int (byte*)> test = [=](byte* start) -> int
    {
        return T::magic(start);
    }; // <--------------------------------- You were missing that
}

struct Foo {
    static int magic(byte*);
};

int Foo::magic(byte* start)
{
    std::cout << "magic\n";
}

int main()
{
    example<Foo>();
}

http://ideone.com/dRdpI

As this appears to be a bug in VC10's lambda implementation, a possible workaround is to create a local functor class:

template<typename T> void example()
{
    struct Foo {
        int operator()(byte * start) { return T::magic(start); }
    };

    std::function<int (byte*)> test = Foo();    
}