I need a quick checksum (as fast as possilbe) for small strings (20-500 chars).
I need the source code and that must be small! (about 100 LOC max)
If it could generate strings in Base32/64. (or something similar) it would be perfect. Basically the checksums cannot use any "bad" chars.. you know.. the usual (){}[].,;:/+-\| etc
Clarifications
It could be strong/weak, that really doesn't matter since it is only for behind-the-scenes purposes.
It need not contain all the data of the original string since I will be only doing comparison with generated checksums, I don't expect any sort of "decryption".
Quick implementation in C, no copyrights from my side, so use it as you wish. But please note that this is a very weak "checksum", so don't use it for serious things :) - but that's what you wanted, isn't it?
This returns an 32-bit integer checksum encoded as an string containing its hex value.
If the checksum function doesn't satisfy your needs, you can change the chk += ((int)(str[i]) * (i + 1));
line to something better (f.e. multiplication, addition and bitwise rotating would be much better).
EDIT: Following hughdbrown's advice and one of the answers he linked, I changed the for
loop so it doesn't call strlen
with every iteration.
#include <stdio.h>
#include <stdlib.h>
#include <string>
char* hextab = "0123456789ABCDEF";
char* encode_int(int i) {
char* c = (char*)malloc(sizeof(char) * 9);
for (int j = 0; j < 4; j++) {
c[(j << 1)] = hextab[((i % 256) >> 4)];
c[(j << 1) + 1] = hextab[((i % 256) % 16)];
i = (i >> 8);
}
c[8] = 0;
return c;
}
int checksum(char* str) {
int i;
int chk = 0x12345678;
for (i = 0; str[i] != '\0'; i++) {
chk += ((int)(str[i]) * (i + 1));
}
return chk;
}
int main() {
char* str1 = "Teststring";
char* str2 = "Teststring2";
printf("string: %s, checksum string: %s\n", str1, encode_int(checksum(str1)));
printf("string: %s, checksum string: %s\n", str2, encode_int(checksum(str2)));
return 0;
}