`date::parse`: no matching overloaded function found

Question

I have installed date library using vcpkg install date:x64-windows and I use find_package(date CONFIG REQUIRED) to use the library in my cross-platform project. I successfully find the library (date_FOUND="1") in C:\Dev\vcpkg\installed\x64-windows\include\date\date.h.

My app uses set(CMAKE_CXX_STANDARD 20) and when I build it using Visual Studio 2022 community, the compiler complains with the following error. I am simply converting a string to a time_point given a format.

const std::string timeString = "2020-12-18 12:30:45";
const char *fmt = "%F";
std::istringstream in(timeString);
std::chrono::time_point<std::chrono::system_clock> timeStamp;
in >> date::parse(fmt, timeStamp);

error C2672: 'date::parse': no matching overloaded function found
C:\Dev\vcpkg\installed\x64-windows\include\date/date.h(8169): note: could be 'unknown-type date::parse(const CharT *,Parsable &,std::basic_string<CharT,Traits,Alloc> &,std::chrono::minutes &)'

It was linked using:

target_link_libraries(main PRIVATE date::date date::date-tz)

I am developing a cross-platform app and therefore, I have installed date library on Linux: ./vcpkg install date:x64-linux.

I can successfully build the same code with gcc11, and it works on Linux.

How can I solve this issue?

Answer 1

This is not a direct solution, but a demonstration of a suggested workaround.

---

Based on Howard Hinnant's comment:

[...] drop from date::parse down to date::from_stream. from_steam offers all of the parse functionality, but is not as nice syntax. And that may work around the issues you're seeing with date::parse and MSVC.

Here's a minimum demo for the problem and my workaround:

#include <iostream>
#include "date/date.h"

int main() {
    std::string time = "2024-05-23";

    std::chrono::system_clock::time_point tp;
    std::stringstream ss(time);

    //ss >> date::parse("%F", tp); //error C2672: 'date::parse': no matching overloaded function found

    date::from_stream(ss, "%F", tp); //Works

    std::cout << tp << "\n";
    return 0;
}